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观察下列式子:1=2×01+1,2=3×12+123=4×23+13,...

(1)解:根据题意得:n=(n+1)?n?1n+1n;(2)证明:∵(n+1)?n?1n+1n=(n+1)(n?1)n+1n=n2?1+1n=n,∴n=(n+1)?n?1n+1n.故答案为:(n+1)?n?1n+1n

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